30 Sep
2009
30 Sep
'09
4:04 p.m.
Hi Chris, IMHO there could be only one multiplex per channel (because frequency corresponds to a channel 1:1 -- you get the frequency using formulae f=1000000*(306+8*c) where c is the channel number).
Probably they got another free frequency (channel) and thus they can start another multiplex.
Regards - Vojtech Horky
Hi Vojtěch Thanks for the reply, that makes sense, so the new frequency should be 762MHz. I misunderstood, as they listed the channels but not frequencies. Regards, Chris