2 multiplexes on the same frequency?

[Chris Hills]

> Hi Chris,
> IMHO there could be only one multiplex per channel (because frequency
> corresponds to a channel 1:1 -- you get the frequency using formulae
> f=1000000*(306+8*c) where c is the channel number).
>
> Probably they got another free frequency (channel) and thus they can
> start another multiplex.
>
> Regards
> - Vojtech Horky

Hi Vojtěch

Thanks for the reply, that makes sense, so the new frequency should be
762MHz. I misunderstood, as they listed the channels but not
frequencies.

Regards,

Chris